Tamil Nadu Board 10th Standard Maths - Chapter 3 Excercise 3.20: Book Back Answers and Solutions
This post covers the book back answers and solutions for Chapter 3 Excercise 3.20 – Maths from the Tamil Nadu State Board 10th Standard Maths textbook. These detailed answers have been carefully prepared by our expert teachers at KalviTips.com.
We have explained each answer in a simple, easy-to-understand format, highlighting important points step by step under the relevant subtopics. Students are advised to read and memorize these subtopics thoroughly. Once you understand the main concepts, you’ll be able to connect other related points with real-life examples and confidently present them in your tests and exams.
By going through this material, you’ll gain a strong understanding of Chapter 3 Excercise 3.20 along with the corresponding book back questions and answers (PDF format).
Question Types Covered:
- 1 Mark Questions: Choose the correct answer, Fill in the blanks, Identify the correct statement, Match the following
- 2 Mark Questions: Answer briefly
- 3, 4, and 5 Mark Questions: Answer in detail
All answers are presented in a clear and student-friendly manner, focusing on key points to help you score full marks.
All the best, Class 10 students! Prepare well and aim for top scores. Thank you!
Chapter 3 Algebra Ex 3.20
(1) intersect only at a point
(2) intersect in a line
(3) coincides with each other
(4) do not intersect
Answer Key:
(1) x = 1, y = 2, z = 3
(2) x = -1, y = 2, z = 3
(3) x = -1, y = -2, z = 3
(4) x = 1, y = 2, z = 3
Answer Key:
(4) x = 1, y = 2, z = 3
Hint:
x + y – 3z = -6
-7y + 7z = 7
3z = 9
z = 3
-7y + 21 = 7
-7y = -14
y = 2
x + 2 -3 × 3 = -6
x + 2 – 9 = -6 .
x = -6 + 7 = 1
(1) 3
(2) 5
(3) 6
(4) 8
Answer Key:
(2) 5
Hint.
HCF = x – 6
p(x) = x2 – 2x – 24
= (x – 6) (x + 4)
g(x) = x2 – kx – 6
∴ x – 6 is the common factor.
g (6) = 62 – k(6) – 6
= 36 – 6k – 6
= 30 – 6k
g(6) = 0
30 – 6k = 0
30 = 6k ⇒ k = = 5
The value of k = 5
(3) (y -
(4) (y +
Answer Key:
(2) (y +
Hint.


%20-%20English%20Medium%20Guides.png)
%20-%20English%20Medium%20Guides.png)

%20-%20English%20Medium%20Guides.png)
(1) 4x2
(2) 16x2
(3) 8x2
(4) -8x2
Answer Key:
(2) 16x2
Hint:
x4 + 64 = (x2)2 + 82 + 2 × 8x2
= (x2 + 8)2
(1) -1
(2) 2
(3) -1, 2
(4) None of these
Answer Key:
(3) -1, 2
Hint.
(2x – 1)2 = 9 ⇒ (2x – 1) = 9–√
2x – 1 = ± 3 ⇒ 2x – 1 = 3 or 2x – 1 = 3
2x – 1 = 3
2x = 4 ⇒ x = 42 = 2
2x – 1 = -3 ⇒ 2x = -3 + 1
x = -1
(1) 100,120
(2) 10,12
(3) -120,100
(4) 12,10
Answer Key:
(3) -120,100
Hint.
Since it is a perfect square
a + 120 = 0
a = -120
b – 100 = 0

(1) A.P.
(2) G.P.
(3) Both A.P and G.P
(4) none of these
Answer Key:
(2) G.P.
Hint.
q2x2 + p2x + r2 = 0
Let the roots be α2 + β2
α2 + β2 =
α2β2 =
qx2 + px + r = 0
Let the root be α and β
%20-%20English%20Medium%20Guides.png)
(1) straight line
(2) circle
(3) parabola
(4) hyperbola
Answer Key:
(1) 0
(2) 1
(3) 0 or 1
(4) 2
Answer Key:
(2) 1
Hint:
(x + 2)2 = 0 ⇒ (x + 2) (x + 2) = 0
x + 2 = 0 or x + 2 = 0 ⇒ x = -2 or x = -2
Number of points of intersection is 1 (both the values are same)
(1) 3
(2) 4
(3) 2
(4) 5
Answer Key:
∴ Number of columns is 4.
(1) diagonal matrix
(2) rectangular matrix
(3) square matrix
(4) identity matrix
Answer Key:
(1) unit matrix
(2) diagonal matrix
(3) column matrix
(4) row matrix
Answer Key:

%20-%20English%20Medium%20Guides.png)

(ii) B2
(iii) AB
(iv) BA
(1) (i) and (ii) only
(2) (ii) and (iii) only
(3) (ii) and (iv) only
(4) all of these
Answer Key:
(3) (ii) and (iv) only
Hint:
(ii) B2 is also possible to find
(iii) not possible: order of A= (3 × 2) order of B is (3 × 3). AB is not possible number of column of matrix A ≠ number of rows of the matrix B.
(iv) Possible number column of the matrix is equal to the number of the matrix A.

(2) (ii) and (iii) only
(3) (iii) and (iv)
(4) all of these
Answer Key:
(1) (i) and (ii) only
Hint.
(i) AB + C : order of A = 2 × 3
order of B = 3 × 2
order of AB = 2 × 2
order of C = 2 × 2
It is possible to add AB + C
order of B = 3 × 2
order of C = 2 × 2
It is possible to find BC
order of B = 3 × 2
order of A = 3 × 2
BA does not exist.
BA + C is not a correct statement
order of A = 2 × 3 order of
B = 3 × 2
order of AB = 2 × 2
order of C = 3 × 2
It is not possible to multiply AB and C.
∴ The statement ABC is not correct.
0 Comments:
Post a Comment