Tamil Nadu Board 10th Standard Science - Physics Unit 3: Book Back Answers and Solutions
This post covers the book back answers and solutions for Unit 3 – Physics from the Tamil Nadu State Board 10th Standard Science textbook. These detailed answers have been carefully prepared by our expert teachers at KalviTips.com.
We have explained each answer in a simple, easy-to-understand format, highlighting important points step by step under the relevant subtopics. Students are advised to read and memorize these subtopics thoroughly. Once you understand the main concepts, you’ll be able to connect other related points with real-life examples and confidently present them in your tests and exams.
By going through this material, you’ll gain a strong understanding of Physics Unit 3 along with the corresponding book back questions and answers (PDF format).
Question Types Covered:
- 1 Mark Questions: Choose the correct answer, Fill in the blanks, Identify the correct statement, Match the following
- 2 Mark Questions: Answer briefly
- 3, 4, and 5 Mark Questions: Answer in detail
All answers are presented in a clear and student-friendly manner, focusing on key points to help you score full marks.
All the best, Class 10 students! Prepare well and aim for top scores. Thank you!
Topic: Thermal Physics
I. Choose the correct Answer
(b) 8.03 mol-1 K-1
(c) 1.38 mol-1 K-1
(d) 8.31 mol-1 K-1
Answer Key:
(d) 8.31 mol-1 K-1
(a) positive
(b) negative
(c) zero
(d) none of the above
Answer Key:
(b) negative
3. If a substance is heated or cooled, the linear expansion occurs along the axis of ______.
(a) X or -X
(b) Y or -Y
(c) both (a) and (b)
(d) either (a) or (b).
Answer Key:
(c) both (a) and (b)
4. Temperature is the average of the molecules of a substance.
(a) difference in K.E and P.E
(b) sum of P.E and K.E
(c) difference in T.E and P.E
(d) difference in K.E and T.E
Answer Key:
(b) sum of P.E and K.E
5. In the Given diagram, the possible direction of heat energy transformation is:
(b) A → B, A → C, B → C
(c) A → B, A ← C, B → C
(d) A ← B, A → C, B ← C
Answer Key:
(a) A ← B, A ← C, B ← C
II. Fill in the blanks
III. State whether the following statements are true or false. if false explain why?
1. For a given heat in liquid, the apparent expansion is more than that of real expansion.2. Thermal energy always flows from a system at higher temperature to a system at lower temperature.
3. According to Charles’s law, at constant pressure, the temperature is inversely proportional to volume.
Answer key:
1. True
2. True
3. False – According to Charles law, at constant pressure, the volume is directly proportional to temperature.
IV. Match the following
Column I |
Column II |
1. Linear expansion |
a. change in volume |
2. Superficial expansion |
b. hot body to cold body |
3. Cubical expansion |
c. 1.381 X 10-23 JK-1 |
4. Heat transformation |
d. change in length |
5. Boltzmann constant |
e. change in area |
Column I |
Column II |
1. Linear expansion |
a. change in length |
2. Superficial expansion |
b. change in area |
3. Cubical expansion |
c. change in volume |
4. Heat transformation |
d. hot body to cold body |
5. Boltzmann constant |
e. 1.381 X 10-23 JK-1 |
V. Assertion & Reasoning
(a) Both the assertion and the reason are true and the reason is the correct explanation of the assertion.(b) Both the assertion and the reason are true but the reason is not the correct explanation of the assertion.
(c) The assertion is true but the reason is false.
(d) The assertion is false but the reason is true.
1. Assertion: There is no effects on other end when one end of the rod is only heated.
Reason: Heat always flows from a region of lower temperature to higher temperature of the rod.
2. Assertion: Gas is highly compressible than solid and liquid
Reason: Interatomic or intermolecular distance in the gas is comparably high.
Answer Key:
1. (b)
2. (a)
VI. Answer briefly
Distinguish between linear and superficial areal expansion.
Answer Key:
Linear Expansion
|
Areal and Superficial Expansion
|
In this expansion, length of a body increases
|
In this expansion, area of a body increases
|
Coefficient of linear expansion is
different for different materials.
|
Coefficient of Areal expansion is
different for different materials.
|
|
|
What is the coefficient of cubical expansion?
Answer Key:
The ratio of increase in the volume of the body per degree rise in temperature to its unit volume is called a coefficient of cubical expansion.
P ∝ 1 / V
i.e., V ∝ T.
(or)
= constant.
Distinguish between ideal gas and real gas.
Answer Key:
Ideal gas |
Real gas |
In this gas molecules or atoms of a gas interact with each other with some interatomic force. |
In this gas molecules or atoms of a gas do not interact with each other. |
They obey Boyle’s law, Charles law and Avogadro’s law. |
They do not obey Boyle’s law, Charles law and Avogadro’s law. |
What is co-efficient of real expansion?
Answer Key:
Coefficient of real expansion is defined as the ratio of the true rise in the volume of the liquid per degree rise in temperature to its unit volume. The SI unit of coefficient of real expansion is the K-1.
What is the coefficient of apparent expansion?
Answer Key:
Coefficient of apparent expansion is defined as the ratio of the apparent rise in the volume of the liquid per degree rise in temperature to its unit volume.
The SI unit of the coefficient of apparent expansion is K-1.
VII. Numerical Problems
Question 1.Find the final temperature of a copper rod whose area of cross section changes from 10 m² to 11 m² due to heating. The copper rod is initially kept at 90 K. (Coefficient of superficial expansion is 0.0021 /K).
Answer Key:
Change in area ΔA = 11 – 10 = 1 m²
Initial temperature T1 = 90 K
Let Final temperature be T2K
A0 = 10 m²
Coefficient of superficial expansion is
αA = 0.0021 / k
= αAΔT
= 0.0021 ΔT
∴ ΔT = 0.0021 × 10
= 0.021
T2 – 90 = 0.021
∴ Final temperature T2 = 90.021 K
Calculate the coefficient of cubical expansion of a zinc bar. Whose volume is increased 0.25 m³ from 0.3 m³ due to the change in its temperature of 50 K.
Answer Key:
Initial volume V0 = 0.25 m³
Final volume = 0.30 m³
Change in volume ΔV = 0.3 – 0.25 = 0.05 m³
Temperature ΔT = 50K
Coefficient of cubical expansion is
αv = 0.004 /K
VIII. Answer in detail
Question 1.Derive the ideal gas equation.
Answer Key:
The ideal gas equation is an equation, which relates all the properties of an ideal gas. An ideal gas obeys Boyle’s law and Charles’s law and Avogadro’s law.
According to Boyle’s law, PV = constant ………. (1)
According to Charles’s law,
According to Avogadro’s law,
= constant …….. (3)
After combining equations (1), (2) and (3), you equation. can get the following
= constant ……. (4)
The above relation is called the combined law of gases. If you consider a gas, which contains µ moles of the gas, the number of atoms contained will be equal to µ times the Avogadro number, N0.
i.e., n = µNA
Using equation (5), in equation (4) can be written as
= constant
The value of the constant in the above equation is taken to be KB, which is called as Boltzmann constant (1.38 × 10-23 JK-1). Hence, we have the following equation:
= KB
PV = µNAKBT
µNAKB = R
which is termed as universal gas constant whose value is 8.31 J mol-1 K-1.
Ideal gas equation is also called as equation of state because it gives the relation between the state variables and it is used to describe the state of any gas.
Question 2.
Explain the experiment of measuring the real and apparent expansion of a liquid with a neat diagram.
Answer Key:
Real expansion =L3 – L2
IX. Hot questions
Question 1.If you keep ice at 0°C and water at 0°C in either of your hands, in which hand you will feel more chillness? Why?
Answer Key:
The hand consisting of ice at 0°C would feel more chillness because, ice undergoes melting. More amount of energy (chillness) is transferred to hand. In addition ice has latent heat of fusion.
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