Tamil Nadu Board 11th Standard Botany - Chapter 15: Book Back Answers and Solutions
This post covers the book back answers and solutions for Chapter 15 – Botany from the Tamil Nadu State Board 11th Standard Botany textbook. These detailed answers have been carefully prepared by our expert teachers at KalviTips.com.
We have explained each answer in a simple, easy-to-understand format, highlighting important points step by step under the relevant subtopics. Students are advised to read and memorize these subtopics thoroughly. Once you understand the main concepts, you’ll be able to connect other related points with real-life examples and confidently present them in your tests and exams.
By going through this material, you’ll gain a strong understanding of Botany Chapter 15 along with the corresponding book back questions and answers (PDF format).
Question Types Covered:
- 1 Mark Questions: Choose the correct answer, Fill in the blanks, Identify the correct statement, Match the following
- 2 Mark Questions: Answer briefly
- 3, 4, and 5 Mark Questions: Answer in detail
All answers are presented in a clear and student-friendly manner, focusing on key points to help you score full marks.
All the best, Class 11 students! Prepare well and aim for top scores. Thank you!
Chapter 15 : Plant Growth and Development
I. Multiple Choice Questions
a. Formative phase of the cells retain the capability division. of cell
b. In elongation phase development of central vacuole takes place.
c. In maturation phase thickening and differentiation takes place.
d. In maturation phase, the cells grow further.
Answer Key:
d. In maturation phase, the cells grow further.
2. If the diameter of the pulley is 12 inches, length of pointer is 10 inches and distance travelled by pointer is 5 inches. Calculate the actual growth in length of plant.
a. 3 inches
b. 6 inches
c. 12 inches
d. 30 inches
Answer Key:
a. 3 inches
3.____________is the powerful growth inhibitor
a. Ethanol
b. Cytokinins
C. ABA
d. Auxin.
Answer Key:
C. ABA
4. Select the correctly matched one
A) Human urine i) Auxin-B
B) Corn gram oil ii) GA3
C) Fungus iii) Abscisic acid II
D) Herring fish sperm iv) Kinitin
E) Unripe maize grains v) Auxin A
F) Young cotton bolls vi) Zeatin
a) A-iii, B-iv, C-v,D-vi, E-i, F-ii,
b) A-v, B-i, C-ii, D-iv, E-vi, F-iii,
c) A-iii, B-v, C-vi, D-i, E-ii, F-iv,
d) A-ii, B-iii, C-v, D-vi, E-iv, F-i
Answer Key:
b) A-v, B-i, C-ii, D-iv, E-vi, F-iii,
5. Seed dormancy allows the plants to
a. overcome conditions unfavourable climatic
b. develop healthy seeds
c. reduce viability
d. prevent deterioration of seeds
Answer Key:
a. overcome conditions unfavourable climatic
6. Which one of the following method are used to break the seed dormancy?
a) Scarification
b) Impaction
c) Stratification
d) All the above.
Answer Key:
d) All the above
II. Short answer questions
aaIII. Long answer questions
aIV. Exercise
a
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