Plus Two / 12th Chemistry - Book Back Answers - Unit 9 - English Medium
Tamil Nadu Board 12th Standard Chemistry - Unit 9: Book Back Answers and Solutions
This post covers the book back answers and solutions for Unit 9 from the Tamil Nadu State Board 12th Standard Chemistry textbook. These detailed answers have been carefully prepared by our expert teachers at KalviTips.com.
We have explained each answer in a simple, easy-to-understand format, highlighting important points step by step under the relevant subtopics. Students are advised to read and memorize these subtopics thoroughly. Once you understand the main concepts, you’ll be able to connect other related points with real-life examples and confidently present them in your tests and exams.
By going through this material, you’ll gain a strong understanding of Unit 9 along with the corresponding book back questions and answers (PDF format).
Question Types Covered:
- 1 Mark Questions: Choose the correct answer, Fill in the blanks, Identify the correct statement, Match the following
- 2 Mark Questions: Answer briefly
- 3, 4, and 5 Mark Questions: Answer in detail
All answers are presented in a clear and student-friendly manner, focusing on key points to help you score full marks.
All the best, Class 12 students! Prepare well and aim for top scores. Thank you!
I. Multiple Choice Questions
1. The number of electrons that have a total charge of 9650
coulombs is
a) 6.22 ×1023
b) 6.022 ×1024
c) 6.022 ×1022
c) 6.022 ×10−34
Answer Key:
c) 6.022 ×1022
2. Consider the following half cell reactions:
Mn2+ + 2e− Mn E° = -1.18V
Mn2+ Mn3+ + e− E° = -1.51V
The E° for the reaction 3Mn2+ Mn+2Mn3+, and the possibility of the forward
reaction are respectively.
a) 2.69V and spontaneous
b) -2.69 and non spontaneous
c) 0.33V and Spontaneous
d) 4.18V and non spontaneous
Answer Key:
b) -2.69 and non spontaneous
3. The button cell used in watches function as follows
Zn (s) + Ag2O (s) + H2O
(l) 2 Ag (s) + Zn2+(aq) +
2OH-(aq) the half cell
potentials are Ag2O (s) + H2O
(l) + 2e− 2Ag (s) + 2OH- (aq) E° = 0.34V
and Zn (s) Zn2+ (aq) + 2e− E° = 0.76V . The cell potential will be
a) 0.84V
b) 1.34V
c) 1.10V
d) 0.42V
Answer Key:
c) 1.10V
4. The molar conductivity of a 0.5 mol dm-3
solution of AgNO3 with electrolytic conductivity of 5.76 ×10−3 S cm−1at 298 K is
a) 2.88 S cm2mol-1
b) 11.52 S cm2mol-1
c) 0.086 S cm2mol-1
d) 28.8 S cm2mol-1
Answer Key:
b) 11.52 S cm2mol-1
5.
Electrolyte
|
KCl
|
KNO3
|
HCl
|
NaOAC
|
NaCl
|
(S cm2mol-1)
|
149.9
|
145.0
|
426.2
|
91.0
|
126.5
|
Calculate using appropriate molar conductances of
the electrolytes listed above at infinite dilution in water at 25°C .
a) 517.2
b) 552.7
c) 390.7
d) 217.5
Answer Key:
c) 390.7
6. Faraday constant is defined as
a) charge carried by 1 electron
b) charge carried by one mole of electrons
c) charge required to deposit one mole of substance
d) charge carried by 6.22 ×1010
electrons.
Answer Key:
b) charge carried by one mole of electrons
7. How many faradays of electricity are required for the
following reaction to occur
MnO4- Mn2+
a) 5F
b) 3F
c) 1F
d) 7F
Answer Key:
a) 5F
8. A current strength of 3.86 A was passed through molten Calcium
oxide for 41minutes and 40 seconds. The mass of Calcium in grams deposited at
the cathode is (atomic mass of Ca is 40g / mol and 1F = 96500C).
a) 4
b) 2
c) 8
d) 6
Answer Key:
b) 2
9. During electrolysis of molten sodium chloride, the time
required to produce 0.1mole of chlorine gas using a current of 3A is
a) 55 minutes
b) 107.2 minutes
c) 220 minutes
d) 330 minutes
Answer Key:
b) 107.2 minutes
10. The number of electrons delivered at the cathode during
electrolysis by a current of 1A in 60 seconds is (charge of electron = 1.6 ×10−19C)
a) 6.22 ×1023
b) 6.022 ×1020
c) 3.75 ×1020
d) 7.48 ×1023
Answer Key:
c) 3.75 ×1020
11. Which of the following electrolytic solution has the
least specific conductance
a) 2N
b) 0.002N
c) 0.02N
d) 0.2N
Answer Key:
b) 0.002N
12. While charging lead storage battery
a) PbSO4 on cathode is reduced to Pb
b) PbSO4 on anode is oxidised to PbO2
c) PbSO4 on anode is reduced to Pb
d) PbSO4 on cathode is oxidised to Pb
Answer Key:
c) PbSO4 on anode is reduced to Pb
13. Among the following cells
I) Leclanche cell
II) Nickel – Cadmium cell
III) Lead storage battery
IV) Mercury cell
Primary cells are
a) I and IV
b) I and III
c) III and IV
d) II and III
Answer Key:
a) I and IV
14. Zinc can be coated on iron to produce galvanized iron but
the reverse is not possible. It is because
a) Zinc is lighter than iron
b) Zinc has lower melting point than iron
c) Zinc has lower negative electrode potential than iron
d) Zinc has higher negative electrode potential than iron
Answer Key:
d) Zinc has higher negative electrode potential than iron
15. Assertion : pure iron when heated in dry air is converted
with a layer of rust.
Reason : Rust has the compositionFe3O4
a) if both assertion and reason are true and reason is
the correct explanation of assertion.
b) if both assertion and reason are true but reason is
not the correct explanation of
assertion.
c) assertion is true but reason is false
d) both assertion and reason are false.
Answer Key:
d) both assertion and reason are false.
16. In H2-O2 fuel cell the reaction occurs at
cathode is
a) O2(g) + 2H2O (l) + 4e− 4OH− (aq)
b) H+(aq) + OH‑ (aq) H2O (2l)
c) 2H2(g) + O2(g) 2H2O
(g)
d) H+ e-
H2
Answer Key:
a) O2(g) + 2H2O (l) + 4e− 4OH− (aq)
17. The equivalent conductance of solution of a weak monobasic acid is 6
mho cm2 equivalent –1 and at infinite dilution
is 400 mho cm2 equivalent –1. The dissociation constant
of this acid is
a) 1.25 ×10−6
b) 6.25 ×10−6
c) 1.25 ×10−4
d) 6.25 ×10−5
Answer Key:
b) 6.25 ×10−6
18. A conductivity cell has been calibrated with a 0.01M, 1:1
electrolytic solution (specific conductance ( 𝛋 =1.25 x 10-3 S cm-1) in the cell
and the measured resistance was 800 Ω at 25°C . The cell constant is,
a) 10−1 c m−1
b) 101 c m−1
c) 1 c m−1
d) 5.7 ×10−12
Answer Key:
c) 1 c m−1
19. Conductivity of a saturated solution of a sparingly
soluble salt AB (1:1 electrolyte) at 298K is 1.85 ×10−5 S m−1. Solubility product of the salt AB at 298K = 14 ×10−3 S m2 mol−1 .
a) 5.7 ×10−12
b) 1.32 ×10−12
c) 7.5 ×10−12
d) 1.74 ×10−12
Answer Key:
d) 1.74 ×10−12
20. In the electrochemical cell: Zn|ZnSO4 (0.01M)|| CuSO4
(1.0M) Cu, the emf of this Daniel cell is E1. When the concentration
of is changed to 1.0M and that CuSO4 changed to 0.01M, the emf
changes to E2. From the above, which one is the relationship between
E1 and E2?
a) E1 < E2
b) E1 > E2
c) E1 ≥ E2
d) E1 = E2
Answer Key:
b) E1 > E2
21. Consider the change in oxidation state of Bromine corresponding
to different emf values as shown in the diagram below:
Then the species undergoing
disproportionation is
a) Br2
b)
c)
d) HBrO
Answer Key:
d) HBrO
22. For the cell reaction
2Fe3+(aq) + 2l−(aq) 2Fe2+ (aq) + l2(aq)
E°.24V cell o = at 298K. The standard Gibbs energy (Δ, G°) of the cell reactions is:
a) -46.32 KJ mol−1
b) -23.16 KJ mol−1
c) 46.32 KJ mol−1
d) 23.16 KJ mol−1
Answer Key:
a) -46.32 KJ mol−1
23. A certain current liberated 0.504gm of hydrogen in 2 hours.
How many grams of copper can be liberated by the same current flowing for the
same time through copper sulphate solution
a) 31.75
b) 15.8
c) 7.5
d) 63.5
Answer Key:
b) 15.8
24. A gas X at 1 atm is bubbled through a solution containing
a mixture of 1MY- and 1MZ- at 25oC. If the reduction potential of
Z>Y>X, then
a) Y will oxidize X and not Z
b) Y will oxidize Z and not X
d) Y will oxidize both X and Z
d) Y will reduce both X and Z
Answer Key:
a) Y will oxidize X and not Z
25. Cell equation : A2++ 2B- A+2B
A2 + + 2e- A Eo = +0.34V
and log10K = 15.6 at 300K for cell reactions find Eo for
B+ + e− B
a) 0.80
b) 1.26
c) -0.54
d) -10.94
Answer Key:
a) 0.80
II. Short Answer Questions.
12th ChemistryIII. Long Answer Questions.
12th ChemistryIV. Exercise.
12th Chemistry
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