Tamil Nadu Board 11th Standard Chemistry - Unit 13 : Book Back Answers and Solutions
This post covers the book back answers and solutions for Unit 13 – Chemistry from the Tamil Nadu State Board 11th Standard Chemistry textbook. These detailed answers have been carefully prepared by our expert teachers at KalviTips.com.
We have explained each answer in a simple, easy-to-understand format, highlighting important points step by step under the relevant subtopics. Students are advised to read and memorize these subtopics thoroughly. Once you understand the main concepts, you’ll be able to connect other related points with real-life examples and confidently present them in your tests and exams.
By going through this material, you’ll gain a strong understanding of Chemistry Unit 13 along with the corresponding book back questions and answers (PDF format).
Question Types Covered:
- 1 Mark Questions: Choose the correct answer, Fill in the blanks, Identify the correct statement, Match the following
- 2 Mark Questions: Answer briefly
- 3, 4, and 5 Mark Questions: Answer in detail
All answers are presented in a clear and student-friendly manner, focusing on key points to help you score full marks.
All the best, Class 11 students! Prepare well and aim for top scores. Thank you!
Unit 13 :Hydrocarbons
I. Choose the best answer.
a) the eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain.
b) the staggered conformation of ethane is more stable than eclipsed conformation,
because staggered conformation has no torsional strain.
c) the staggered conformation of ethane is less stable than eclipsed conformation,
because staggered conformation has torsional strain.
d) the staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has no torsional strain.
Answer Key:
b) the staggered conformation of ethane is more stable than eclipsed conformation,
2. C2H5 Br + 2Na C4H10 + 2NaBr The above reaction is an example of which of the following
a) Reimer Tiemann reaction
b) Wurtz reaction
c) Aldol condensation
d) Hoffmann reaction
Answer Key:
b) Wurtz reaction
3.An alkyl bromide (A) reacts with sodium in ether to form 4, 5–diethyloctane, the compound (A) is
a) CH3 (CH2)3 Br
b) CH3(CH2)5 Br
c) CH3(CH2)3 CH(Br)CH3
d) CH3 – (CH2)2 – CH (Br)
Answer Key:
4.The C – H bond and C – C bond in ethane are formed by which of the following types of overlap
a) sp3 – s and sp3 – sp3
b) sp2 – s and sp2 – Sp2
c) sp – sp and sp – sp
d) p – s and p – p
Answer Key:
a) sp3 – s and sp3 – sp3
5.In the following reaction,



b) citric acid
c) Glycerol
d) none of of these
Answer Key:
d) none of of these
7. The compounds formed at anode in the electrolysis of an aquous solution of potassium acetate are
a) CH4 and H2
b) CH4 and CO2
c) C2H6 and CO2
d) C2H4 and Cl2
Answer Key:
c) C2H6 and CO2
8. The general formula for cyclo alkanes
a) CnHn
b) CnH2n
c) Cn H2n–2
d) Cn H2n+2
b) CnH2n
9. The compound that will react most readily with gaseous bromine has the formula (NEET)
a) C3H6
b) C2H2
c) C4H10
d) C2H4
Answer Key:
a) C3H6
10. Which of the following compounds shall not produce propene by reaction with HBr followed by elimination (or) only direct elimination reaction
(NEET)
a)
b) CH3 – CH2 – CH2 – OH
c) H2C = C = 0
d) CH3 – CH2 – CH2Br
Answer Key:
c) H2C = C = 0
11. Which among the following alkenes on reductive ozonolysis produces only propanone ?
a) 2 – Methyl propene
b) 2 – Methyl but – 2 - ene
c) 2, 3 – Dimethyl but – 1 – ene
d) 2, 3 – Dimethyl but – 2 – ene
Answer Key:
d) 2, 3 – Dimethyl but – 2 – ene
12. The major product formed when 2 – bromo – 2 – methyl butane is refluxed with ethanolic KOH is
a) 2 – methylbut – 2 – ene
b) 2 – methyl butan – 1 – ol
c) 2 – methyl but – 1 – ene
d) 2 – methyl butan – 2 – ol
Answer Key:
a) 2 – methylbut – 2 – ene
13. Major product of the below mentioned reaction is,
(CH3)2 C = CH2
a) 2–chloro –1– iodo – 2 – methyl propane
b) 1–chloro–2–iodo–2–methylpropane
c) 1,2 – dichloro – 2 – methyl propane
d) 1, 2 – diiodo – 2 – methyl propane
Answer Key:
a) 2–chloro –1– iodo – 2 – methyl propane
14. The IUPAC name of the following compound is

b) cis–3 – iodo – 4 – chloro – 3 – pentane
c) trans–3–iodo–4–chloro – 3 – pentene
d) cis–2 – chloro – 3 – iodo – 2 – pentene
Answer Key:
a) trans–2–chloro–3–iodo – 2 – pentene
15. Cis – 2 – butene and trans – 2 – butane are
a) conformational isomers
b) structural isomers
c) configurational isomers
d) optical isomers
Answer Key:
c) configurational isomers
16. Identify the compound (A) in the following reaction



a) Zn
b) Conc H2SO4
c) alc. KOH
d) dil H2SO4
Answer Key:
c) alc. KOH
18. Consider the nitration of benzene using mixed con H2SO4 and HNO3 if a largem quantity of KHSO4 is added to the mixture, the rate of nitration will be
a) unchanged
b) doubled
c) faster
d) slower
Answer Key:
d) slower
19. In which of the following molecules, all atoms are co-planar

d) both (a) and (b)
20. Propyne on passing through red hot iron tube gives







a) Nitro benzene
b) Toluene
c) Cumene
d) Xylene
Answer Key:
a) Nitro benzene
24. Some meta-directing substituents in aromatic substitution are given. Which one is most deactivating ?
a) – COOH
b) – NO2
c) – C ≡ N
d) – SO3H
Answer Key:
b) – NO2
25. Which of the following can be used as the halide component for friedal – crafts reaction ?
a) Chloro benzene
b) Bromo benzene
c) chloro ethene
d) isopropyl chloride
Answer Key:
d) isopropyl chloride
26. An alkane is obtained by decarboxylation of sodium propionate. Same alkane can be prepared by
a) Catalytic hydrogenation of propene
b) action of sodium metal on iodomethane
c) reduction of 1 – chloro propane
d) reduction of bromomethane
Answer Key:
b) action of sodium metal on iodomethane
27. Which of the following is aliphatic saturated hydrocarbon
a) C8 H18
b) C9 H18
c) C8 H14
d) All of these
Answer Key:
a) C8 H18
28. Identify the compound 'Z' in the following reaction
a) Formaldehyde
b) Acetaldehyde
c) Formic acid
d) none of these
Answer Key:
a) Formaldehyde
29. Peroxide effect (Kharasch effect) can be studied in case of
a) Oct – 4 – ene
b) hex – 3 – ene
c) pent – 1 – ene
d) but – 2 – ene
Answer Key:
c) pent – 1 – ene
30. 2 – butyne on chlorination gives
a) 1 – chloro butane
b) 1, 2 – dichloro butane
c) 1, 1, 2, 2 – tetrachlorobutane
d) 2, 2, 3, 3 – tetra chloro butane
Answer Key:
d) 2, 2, 3, 3 – tetra chloro butane
II. Short Answer Questions
11th ChemistryIII. Long Answer Questions
11th ChemistryIV. Exercise
11th Chemistry







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